Nos Case

Another case in solving equalities in algebra?

How do you solve these kinds of problem(solving equalities)

1. 2n/8 = 3 (The slash indicates a fraction meaning 2n/8 is a fraction)

2. 1/4 = 9

3. -x/5 = -12

4. 2/7 (x) = 28

5. 2x/16 = 23

PLEASE! I need explanation!Especially nos. 1,2,4 and 5

Thanks in advance!

How do you solve these kinds? I know how to solve the other cases but i need to know the way on how to solve this.
How did you get 8 at no. 5?How do you take the common factor of 2 as a fraction?
Ok! I got it thanks!

1.

2n/8 = 3

simplify the fraction by taking a common factor of 2 out.

n/4=3

multiply both sides by 4

n=12

2.

this is incorrect, youve made a typo... 1/4 cannot equal 9.

3.

-x/5 = -12

multiply both sides by -5

x= 60

4.

2/7 (x) = 28

multiply both sides by 7

2x=196

divide both sides by 2

x = 98

5.

2x/16 = 23

take out common factor of 2 in fraction

x/8 = 23

multiply both sides by 8

x=184

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